Segment Tree Modify
36% Accepted
For a Maximum Segment Tree,
which each node has an extra value max to store the maximum value in this node's interval.
Implement a modify function with three parameter root, index and value to change the node's value with [start, end] = [index, index] to the new given value. Make sure after this change, every node in segment tree still has the max attribute with the correct value.
Have you met this question in a real interview? Yes
Example
For segment tree:
[1, 4, max=3]
/ \
[1, 2, max=2] [3, 4, max=3]
/ \ / \
[1, 1, max=2], [2, 2, max=1], [3, 3, max=0], [4, 4, max=3]
if call modify(root, 2, 4), we can get:
[1, 4, max=4]
/ \
[1, 2, max=4] [3, 4, max=3]
/ \ / \
[1, 1, max=2], [2, 2, max=4], [3, 3, max=0], [4, 4, max=3]
or call modify(root, 4, 0), we can get:
[1, 4, max=2]
/ \
[1, 2, max=2] [3, 4, max=0]
/ \ / \
[1, 1, max=2], [2, 2, max=1], [3, 3, max=0], [4, 4, max=0]
Note
We suggest you finish problem Segment Tree Build and Segment Tree Query first.
Challenge
Do it in O(h) time, h is the height of the segment tree.
Tags Expand
- LintCode Copyright
- Binary Tree
- Segment Tree
思路
- 递归,简单题 O(nlogn)
- 可以简化为一层递归 O(h)
/**
* Definition of SegmentTreeNode:
* public class SegmentTreeNode {
* public int start, end, max;
* public SegmentTreeNode left, right;
* public SegmentTreeNode(int start, int end, int max) {
* this.start = start;
* this.end = end;
* this.max = max
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
*@param root, index, value: The root of segment tree and
*@ change the node's value with [index, index] to the new given value
*@return: void
*/
public void modify(SegmentTreeNode root, int index, int value) {
if (root == null || index > root.end || index < root.start) {
return;
}
updatenode(root, index, value);
root.max= updatemax(root);
}
public void updatenode(SegmentTreeNode root, int index, int value) {
if (root == null || index > root.end || index < root.start) {
return;
}
if (index == root.end && index == root.start) {
root.max = value;
return;
}
if (index <= root.left.end) {
updatenode(root.left, index, value);
}
if (index >= root.right.start) {
updatenode(root.right, index, value);
}
root.max = Math.max(root.left.max, root.right.max);
}
public int updatemax(SegmentTreeNode root) {
if (root.start == root.end) {
return root.max;
}
int left = updatemax(root.left);
int right = updatemax(root.right);
root.max = Math.max(left, right);
return Math.max(left, right);
}
}
改变后简化写法
- 就改变了一行
- 取消了Update函数,直接在Updatenode中,置换max
- O(h)
/**
* Definition of SegmentTreeNode:
* public class SegmentTreeNode {
* public int start, end, max;
* public SegmentTreeNode left, right;
* public SegmentTreeNode(int start, int end, int max) {
* this.start = start;
* this.end = end;
* this.max = max
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
*@param root, index, value: The root of segment tree and
*@ change the node's value with [index, index] to the new given value
*@return: void
*/
public void modify(SegmentTreeNode root, int index, int value) {
if (root == null || index > root.end || index < root.start) {
return;
}
updatenode(root, index, value);
//root.max= updatemax(root);
}
public void updatenode(SegmentTreeNode root, int index, int value) {
if (root == null || index > root.end || index < root.start) {
return;
}
if (index == root.end && index == root.start) {
root.max = value;
return;
}
if (index <= root.left.end) {
updatenode(root.left, index, value);
}
if (index >= root.right.start) {
updatenode(root.right, index, value);
}
root.max = Math.max(root.left.max, root.right.max);
}
}